Homework Help Math

Teachers ofttimes matter the students with national assignments or schoolwork to apply lessons at plate and to be legible with the lesson taught in the teaching. Preparation also helps the pupil to be indulged in studies regularly.
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Geometry Tutor

Now a days tuition becomes part & parcel in the scholars life.Now a days every students need tuition,because they have lots of confusion regarding their subjects.

For every students are not equal.If one is fast than other one is not. for every students its impossible to get all the chapter whatever done in the class.But it even feasible for some one.And & a teacher couldn’t asked all the each students,are they the idea or not?Teacher couldn’t go through all the idea mention in the book.Because they has to complete the coursework at time.So, to get clear all the idea students need tuition's.Before they had nose to nose tuition.But the expertise helps the scholars to get online tutoring by sitting at home.In online tutoring students & teacher meets through multimedia tool & communicate with each other properly.Online tutors are highly specialist in their respective subjects.
Geometry tutors are the most specialist teacher who are giving service through web to the scholars all around the globe.Even they have free math tutors,free algebra tutors,calculus tutor etc.These all tutors are nice in their subjects & provide high quality service to the scholars.More over they are available 24 hours for help.Students couldn’t find any difference from the class.


These tutors are provide great service to ther students to get more advanced.

Free Calculus Tutor

Tutor gives tuitions to its students.Why students needs tuitions?Because for its and every student its not possible to get all the concept whatever done in the class.And also a class teacher couldn’t asked all the each students they are getting the concept or not.Teacher couldn’t go through all the concept mention in the book.So,every student couldn’t get the concept clearly.To clearify all the concept students need tuitions.Previously we had face to face tuition.But the improvements of technology help the students to get online tutoring.In online tutoring students and teacher meets through multimedia device and communicate with each other.These tutors are highly expert in their subjects.

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Free Algebra Word Problem

In this blog we are going to see free algebra word problems.

The first actual work in arithmetic is free algebra word. Depending upon principles of arithmetic that already have studied, free algebra word makes use of symbols to generate generic solutions which work in various cases.

Free algebra word issue is a kind of textbook word issue designed to help students apply abstract mathematical ideas to real-world situations.

There are s numbers of boys in the class. This is three over two times the number of girls. How lots of numbers of girls are present in the class?
Solution:
Let x represent the unknown number.
Let x represents the number of girls.
Here b is three over two times x:
5x + 3 = s.
In right side, the +3 will become -3
5x = s − 3
x = (s-3) / 5
Here the solution is not a number, because it will be contingent on the worth of b. This is a kind of very common in free algebra word.

this is just an example on free algebra word problems.Go through online you will get more algebra word problem.Also you can get free math problems ,solved precalculus problems,online math word problems etc..through online services.

volume formula help

I believed that you got the albegra expression concept now.So,try to solve some problems from algebra expression worksheet.

To know more about this kind of concept than try to see free algebra help.There you will get more math problems.Also if you need help in calculus than try free calculus help.

Volume formula help

The volume of a quantity of the geometrical shapes is given below: -

Volume formula of a cube = Cube =side x side x side

Volume formula of a Rectangular Prism = Rectangular Prism= side1 x side2 x side3

Volume formula of a Sphere = Sphere=4/3 x pi x radius

Volume formula of a Ellipsoid = Ellipsoid=4/3 x pi x radius1 x radius2 x radius3

Volume formula of a Cylinder = Cylinder=pi x radius x radius x height

Volume formula of a Cone = Cone=1/3 x pi x radius x radius x height

Volume formula of a Pyramid = Pyramid=1/3 x base area x height

Volume formula of a Torus = Torus=1/4 x pi x pi x (r1+r2) x (r1-r2) 2

This are all different volume formula.To get online help on this concept you can go for online volume formula help.

Also if you need help on algebra like free pre algebra help,calculas help,math online help etc..you can get online help for every subject.

Algebra expression worksheet

Algebra expression worksheet

Algebra expressions is the method of expressing or writing an equation that may be several types of Equations in Algebra like algebra Linear equations, Equations containing radicals, Quadratic equations, Equations involving Fractions, Exponential equations, Logarithmic equations etc…

To write an Algebra equation or Algebra expressions we use various methods: -

Addition

Subtraction

Multiplication

Division

Parenthesis: -

( ) first bracket

{ } second bracket

[ ] third bracket

Variable: - x, y, z are generally used as a variable in algebra, variables are those whose values always change. Algebra expressions can be of

One variable

Two variable

Three variable

Example of Algebra expressions are: -

1. x - 4 = 10

2. ax²+bx+c=0

3. x³ + ax² + bx +c = 0

I believed that you got the albegra expression concept now.So,try to solve some problems from algebra expression worksheets.

To know more about this kind of concept than try to see free algebra help.There you will get more math problems.Also if you need help in calculus than try free calculus help.

Volume Formula

In this blog we are going to learn about volume formula.

Volume is the measure of how much space the object takes up or the capacity of the container.

We can calculate the volume of any hollow geometrical shapes with the help of several formulas. To know about valume formula see online math.

The volume of some of the geometrical shapes is given below: -

Volume formula of a cube = Cube =side x side x side

Volume formula of a Rectangular Prism = Rectangular Prism= side1 x side2 x side3

Volume formula of a Sphere = Sphere=4/3 x pi x radius

Volume formula of a Ellipsoid = Ellipsoid=4/3 x pi x radius1 x radius2 x radius3

Volume formula of a Cylinder = Cylinder=pi x radius x radius x height

Volume formula of a Cone = Cone=1/3 x pi x radius x radius x height

Volume formula of a Pyramid = Pyramid=1/3 x base area x height

Volume formula of a Torus = Torus=1/4 x pi x pi x (r1+r2) x (r1-r2) ²

To know more about more this kind of concept see 5th grade math help.It will be benifited for you.

Free Geometry Help

Free geometryhelp Online is where the student and tutor do not meet face to face but meets through multimedia devices like Webcams, Microphone, and Headset etc with the help of internet service.

There are certain benefits of free geometry help.

There can help you solve several types of every concept of geometry like angle,triangle etc.

Free geometry help are available 24/7 round the clock and students can solve their problem through live online chat and emails so students have the flexibility to study at any time.

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Subject experts teachers are provided to students for helping them in their Pre Algebra help. So, every concept is cleared and explicated very well.

It can help in the clearing of the doubts of geometry which sometimes remain unlearned in the class. This helps the student to be much advance in the class and do better in his exam.

This service can assist the student to do his homework in time and he will be much confident in the class as each and every concept will be cleared by the homework helper.

They provide high quality service, complete the assignments accurately which assist the students to do their work more effectively.

To know more about geometry you can see online geometry help.It will help you more.Try to get free math homework help through online.

Online Help

Online help is a modern method of tutoring where the tutor and student do not meet face to face but meets through multimedia devices like Webcams, Microphone, and Headset etc with the assistance of internet service. Though online help is a very advantageous method over the conventional face to face learning, parents are very choosy in their selection of tutors and tutorials as they are very concerned about their child. So, they desire to use the service of the best online tutor company. The tutors should always concentrate in making the class more and more interactive and interesting to provide the best service to the students.Services like:math help online,geometry help online,algebra help onlne,free math help etc..

Here are some guidelines to make online help interactive and interesting: -
Online help become interesting and effective with the help of voice, video, animations, text, graphics etc. Though these things are used by the tutors so that the students find it very effective to learn the concept.
Online help Tutors use the best materials, interactive content, to explain the students. They try to create interactive content by their own then using the old and generally used content.
Online help is available 24/7 all around the globe.
The resources used by the online tutors to teach the subjects effective and relevant which can make the students well prepared for their academic exam or any other entrance

valume of a rectangle

In this blog we are going to learn about how to calculate volume of a rectangle. Also see the given link to know about how to find volume?

In Rectangle two opposite sides are equal and parallel and the measure of each angle is 90 degree. It is also an example of a parallelogram.

Volume of a rectangle is the measure of how much space the object takes up.

Volume of a rectangle can be calculated by taking the length (l), breadth (b), and height (h).

Here is the area of rectangle formula is given below:

V=l X b X h

Where,

V=Volume of Rectangle

l=Length of Rectangle

b=Breadth of Rectangle

h=Height of Rectangle.

The unit for the Volume of Rectangle is m ³ (metre cube).

Next time we will solve some problems on how to calculate area of a rectangle using this formula .To know more about geometry concept i would like suggest you to go for online geometry word problems to know more about geometry concept.

3rd Grade Math

Here is the brief discussion about 3rd grade math.

Arithmetic is one of the basic knowledge to be known. Without arithmetic, it is hard to survive in day to day life. Arithmetic plays a key role in our day to day. 3rd grade math are the math issues that are completed in the grade 3. 3rd grade math words include topics like arithmetic issues such as addition, subtraction, multiplication & division. Some other chapters also include in 3rd grade math words such as numbers & comparing, place value, logical reasoning, graph, time, measurement etc. 3rd grade math are basic of arithmetic. Rounding numbers, equation & statistics also include with 3rd grade math words. The following topics are covered in 3rd grade math,

Numbers

Measures

Algebra

Geometry

Data handling

Next time we are going to discuss about 3rd grade math problems and fifth grade math concept.I believed you get the above mention concept what is 3rd grade math.

5 meter in feet

5 meter in feet

In this blog we are going to discuss about meters to feet conversion.

Meter is based unit of length in the international system of unit(SI) and feet is also measurement of length but it’s a non SI unit.

Here 1 meter =3.2808399 feet.and

1 feet =0.3048 meters

Formula for converting meter to feet-

X meter = 3.2808399 * X feet.

Now come tio the main topic 5 meters in feet.

Here is the solution.

By plugging in the 5 meters in the formula we get

5 meter = 3.2808399 * 5 feet

= 16.40feet.

Therefore, 5 meter is 16. 40 feet.

Using this formula we can convert meters to feet.Now here is a problem for you to solve-

Convert 105 meters to feet.

Use this above mention formula and try to solve this problems.

Prime numbers 100

In this blog we are going to discuss about prime numbers.Before that we should know what is Prime numbers.

The Greek Eratosthenes created a method to find out these prime numbers, although it only worked over a limited range.

In mathematics, a prime number (or a prime) is a natural number that has exactly two different natural number divisors.

Prime numbers are those numbers (greater than 1) that cannot be divided by any number except themselves and one.

The Greek Eratosthenes created a method to find out these prime numbers, although it only worked over a limited range.

Here is list of prime numbers to 100

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.

There are 25 prime numbers in between 1 to 100.

So, now try to find out more prime number after 100.

Formula for Sine

In this blog we are going to learn about formula for sin and sin rule formula.
Definition for sine:Based on tringle.

See the given any angle q (0 £ q £ 90°), we can find the sine of that angle by constructing a right triangle with one vertex of angle q. The sine is equal to side opposite to q( length), divided by the length of the triangle's hypotenuse. In this way, we can find the sine of any q in the range 0 £ q £ 90°.

Formula to do Sine.

• Sin(x+y) = sin(x) cos(y) + cos(x) sin(y).
• Sin(x-y) = sin(x) cos(y) – cos(x) sin(y).
• Sin (2x) = 2sin(x) cos(x).

These are the formula for sine.Now get some knowledge on sine rule.

A sine rule is a formula which is used to findout the unknown in a non right triangle. Sine rule is about an equation in which relating to side length and angle of a triangle. Sine rule is also known as Law of sines.

Here is the sine rule formula.

Sin(A)/a= sin(B)/b=sin(C)/c

This is the sin rule formula .Next time we will learn some solved problems on formula for sine and sine rule based problems.

Enrich Maths

Enrich maths

In this blog we are going to discuss about what is enrich maths and how it helpful to the students to learn mathematics.

Enrich Maths is a collection of activities that aims, through challenging enrichment work, to inspire more children to study mathematics that means to do more maths work, to encourage mathematic amongst all students, to stimulate creativity with regard to mathematical thinking and to promote an informed debate amongst students about the application and direction which mathematics takes in our increasingly complex society.

Enriching Maths will allow you to:

Enrich maths lessons for all students and provide material that will challenge more able students

Improve performanceof students in this core subject by enriching the curriculum

Enhance enjoyment of students of maths and promote it as a subject for further study

Support every improvement by raising standards in core subjects

Provide good opportunities for students to expand their thinking skills through problem-solving and develop their social skills through teamwork

Improve ability of students to self-direct their individual learning and help them to have fun and gain pleasure from thinking.

This is what we can say about enrich math.Its inspire the students to learn more and more maths.

List prime numbers

In this blog we are going to discuss about prime number list.Now, do you know what is prime number?

In mathematics, a prime number (or a prime) is a natural number that has exactly two different natural number divisors.

Some important point on prime numbers-

• The only even prime number is 2. All other even numbers can be divided by 2.
• If the sum of a number's digits is a multiple of 3, that number can be divided by 3.
• No prime number greater than 5 ends in a 5. Any number greater than 5 that ends in a 5 can be divided by 5.
• Zero and 1 are not considered prime numbers.
• Except for 0 and 1, a number is either a prime number or a composite number. A composite number is defined as any number, greater than 1, that is not prime.

Here is a list prime numbers up to 1,000:

2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311 313 317 331 337 347 349 353 359 367 373 379 383 389 397 401 409 419 421 431 433 439 443 449 457 461 463 467 479 487 491 499 503 509 521 523 541 547 557 563 569 571 577 587 593 599 601 607 613 617 619 631 641 643 647 653 659 661 673 677 683 691 701 709 719 727 733 739 743 751 757 761 769 773 787 797 809 811 821 823 827 829 839 853 857 859 863 877 881 883 887 907 911 919 929 937 941 947 953 967 971 977 983 991 997.

By seeing this list try to identify more primre numbers.Next time we will discuss more about this concept

Elementary Statistics

Here in this blog we are going to discuss about Elementary Statistics.But before that we should know what is statistics?Statistics is the scientific application of mathematical principles to the collection, analysis, and presentation of numerical data. Statisticians contribute to scientific enquiry by applying their mathematical and statistical knowledge to the design of surveys and experiments

Elementary Statistics:

In statistics, the mean, median, range, and mode these are very important and very simple terms in the elementary statistics.Here two of the elementary statistics given below with solution.

Mean:

In help with elementary statistics help, the mean is one of the major terms in statistics.

Now we will discuss with the thought of mean.

The mean is give facts about the average of the given numbers.

Here we will find the addition of the given numbers and divided by the total numbers of the given numbers.

The given numbers are 11, 20, 10.

Solution:

The given numbers are 11, 20, 10.

Now adding the given numbers.

=11+20+10=41.

The total of the given numbers are 41.

Now divided by 3, because (Notes: 3 is the total given numbers)

41 /3=13.67.

So the mean value in this series is 13.67.

Median:

In help with elementary statistics help, the median is express about the average value of the given series.

The number series are 11, 20, 10.

Solution:

The given numbers are 11, 20, 10.

In this given numbers, the 20 is the midpoint.

So the 20 is the median of the given series.

Next time we will discuss about the two other types of elementary statistics rang and mode.

How to find the Area of a Quadrilateral

In this blog we are going to learn about a geometry concept Quadrilateral.Before that we should know the qudrilaterral difinition.

Quadrilateral is a 2-dimensional closed shape with four straight sides.Also a a QUADRILATERAL is a polygon with four sides. The parts of a quadrilateral are its sides, its four angles, and its two DIAGONALS.Is this confusing for you to understand this definition I will make it easy for you.

Quadrilateral is a geometry figure which have four sides and four vertices.Also called as polygon. Quadrilaterals can be simple or complex, and also simple quadrilateral are convex or concave.The interior angles of a simple quadrilateral can be 360 degree. Inthis blog we will learn How to find the area of a quadrilateral or Area of the quadrilaterals.

Now I am going to mention the area formulas for quadrilaterals.Using those formula we can find different problems on quadrilaterals.Now look at the formulas.

Square:

Formula:

Area of square = side x side square unit.

Area of square (A) = a² square units,

Perimeter of the square = 4 x side

Rectangle:

Formula:

Area of the rectangle (A) = length x width

Area (A) = l x w

Trapezoid:

Formula:

The formula used for figuring out the area of the trap is given below,

Area of trapezoid (A) = 1/2x h x (a + b) square units

Kite:

Formula:

Area of kite (A) = half the product of two diagonals.

d₁, d₂ - two diagonal of kite.

Area of kite (A) = d1.d2/2square unit.

Trapezoid:

Find the area of trapezoid whose height 12 cm, side a=4 cm and side b= 8 cm

Solution:

Given:

Height (h) =12 cm

Side a= 4 cm; b= 8 cm

Example:Find the area of trapezoid whose height 12 cm, side a=4 cm and side b= 8 cm

By learning formula for area of trapezoidal we can find the area of the trapezoidal.

Area of trapezoid (A) = 1/2x h x (a + b) square units

=1/2 x 12 x (4 + 8)

=1/2 x 12 x 12

=1/2 x 144

= 144/2

= 72

Area of trapezoid (A) = 72 cm²

Next time we will learn more about how to find the area of a quadrilateral solved problems.I believed that this blog will be benefited for you.Next blog we will discuss how to useother formulas also.

Adding and Subtracting radicals problems

Adding and Subtracting radicals problems:

We can identify radicals by seeing the root sign.Also root having in radicals can be either square root or cubic root or any other root.there are three types of radicals expression radical symbols,radicand and another is index.Radicals are defined as the term of having the root.

So in this blog we are going to learn some adding radicals and subtracting radicals.Here is the example for adding and subtracting radicals problems-

Problems: Simplify the equation for adding and subtracting radicals: √ (64) / (√36)

Solution:

Step 1: Factors of 64 = 8× 8

√ (64) = √ (8 × 8)

= √8²

Step 2: Square root of 8² = 8; we know n = x , here n = 2

Step 3: Factors of 36 = 6 × 6

√ (36) = √ (6 × 6) = √6²

Step 4: √62 = 6 ; we know n = x , here n = 2

Step 5: so, √ (64) / √36) = 8 / 6

Answer of the given radical is 8 / 6.

This is only one example of adding radicals and subtracting radicals.Next time we will learn more about this concept.

Circle Properties

circle properties

A circle is a simple shape of Euclidean geometry consisting of different parts centre,diameter,radius etc.i believed that you every body aware of it .So,in this blog we will discuss about circle properties and its different formula.Let’s begin with circle properties.

• The arc of a circle contains two points on the circle and all of the points on the circle that lie between those two points.

• Chord is a segment and having end points which is on a circle.

• Diameter of circle:

Length of the diameter = 2 × length of the radius.

• Circumference of a Circle:

Circumference = 3 × diameter (approx.).

These are the properties of learning circles.

Formulas of circles:

The area of a circle:

Area of circle = 'pi' * r²

where, r is the radius of the circle.

The diameter of circle:

Diameter of circle = 2 * r.

where, r is radius of the circle.

The circumference of circle:

Circumference of circle = 2* 'pi' *r (or) 'pi' *d.

where,r is the radius of the circle.

d is the diameter of the ci

Next time we will solve problems on circle formula.

Area of a Rectangle Formula

Area of a rectangle formula

Rectangle is a quadrilateral (figure bounded by four sides) where the two opposite sides are equal and parallel and the measure of each angle is 90 degree. It is also an example of a parallelogram.

Formula for area of rectangle formula:

Area of rectangle = length x breadth

To find the area of a region for enclosed plane figure, we have to draw a figure and write an appropriate formula. Then substitute the given values, and calculate the required area.

Steps for finding the dimension of the rectangle by using the Area of an rectangle formula:

Step 1: First we have to assign variables:

Step 2: Write area of rectangle formula A = lw

Step 3: Plug given the values from the question

Use distributive to remove brackets

Put in Quadratic form

It can be rewritten as two different squares.

Factorize the two squares.

Now, we get two x values

Using this formula and steps we can calculate valume of a rectangle.Next time we will learn more about rectangle solve problems and examples.

Area of a triangle problems

Area of a triangle problems

In this blog we are going to learn area of a triangle formula and how to solve area of triangle problems.

Formula to find area of a Triangle:

Area of right triangle (A) = 1/2b x h square units

b – Base

h – Height

Area of equilateral triangle (A) = a² √3/4

a – side length

Below there is a solve area of a triangle Problem example-

The triangle angle has base 5 cm and height 13 cm. figure the area of right triangle

Solution:

Base=5cm; height=13

Solve for area:

Formula:

Area of triangle (A) = 1/2(b x h) square units

= 1/2(5 x 13)

= 65/2

Area of triangle (A) =32.5 cm

Next time we will solve more example on area of a triangle.