How to find the Area of a Quadrilateral

In this blog we are going to learn about a geometry concept Quadrilateral.Before that we should know the qudrilaterral difinition.

Quadrilateral is a 2-dimensional closed shape with four straight sides.Also a a QUADRILATERAL is a polygon with four sides. The parts of a quadrilateral are its sides, its four angles, and its two DIAGONALS.Is this confusing for you to understand this definition I will make it easy for you.

Quadrilateral is a geometry figure which have four sides and four vertices.Also called as polygon. Quadrilaterals can be simple or complex, and also simple quadrilateral are convex or concave.The interior angles of a simple quadrilateral can be 360 degree. Inthis blog we will learn How to find the area of a quadrilateral or Area of the quadrilaterals.

Now I am going to mention the area formulas for quadrilaterals.Using those formula we can find different problems on quadrilaterals.Now look at the formulas.

Square:

Formula:

Area of square = side x side square unit.

Area of square (A) = a² square units,

Perimeter of the square = 4 x side

Rectangle:

Formula:

Area of the rectangle (A) = length x width

Area (A) = l x w

Trapezoid:

Formula:

The formula used for figuring out the area of the trap is given below,

Area of trapezoid (A) = 1/2x h x (a + b) square units

Kite:

Formula:

Area of kite (A) = half the product of two diagonals.

d₁, d₂ - two diagonal of kite.

Area of kite (A) = d1.d2/2square unit.

Trapezoid:

Find the area of trapezoid whose height 12 cm, side a=4 cm and side b= 8 cm

Solution:

Given:

Height (h) =12 cm

Side a= 4 cm; b= 8 cm

Example:Find the area of trapezoid whose height 12 cm, side a=4 cm and side b= 8 cm

By learning formula for area of trapezoidal we can find the area of the trapezoidal.

Area of trapezoid (A) = 1/2x h x (a + b) square units

=1/2 x 12 x (4 + 8)

=1/2 x 12 x 12

=1/2 x 144

= 144/2

= 72

Area of trapezoid (A) = 72 cm²

Next time we will learn more about how to find the area of a quadrilateral solved problems.I believed that this blog will be benefited for you.Next blog we will discuss how to useother formulas also.